Python如何优雅的求解10*10矩阵任意两点距离，不使用函数

import numpy as np

# 例题：如何求解距离矩阵
demo_arr = np.empty((10, 10))
for i in range(10):
    demo_arr[i] = np.arange(i, i + 10)
print(demo_arr[:10, :10])
a = ['一', '二']
b = ['横', '纵']
ls = []
for i in a:
    for j in b:
        c = eval(input("请输入第{}个数字{}坐标:".format(i, j)))
        ls.append(c)
a = ls[0]
b = ls[1]
c = ls[2]
d = ls[3]

s = np.sqrt((c - a) ** 2 + (d - b) ** 2)
print(s)

运行结果：