51单片机：编程实现LED点阵显示心形向上移动

点阵取模 

#include <reg52.h>

sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;
sbit ENLED = P1^4;

unsigned char code image[] = {  //图片的字模表
0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,
0xFF,0xFF,0xFF,0x99,0x00,0x00,0x00,0x81,0xC3,0xE7,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,
0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF
};

void main()
{
    EA = 1;       //使能总中断
    ENLED = 0;    //使能U4，选择LED点阵
    ADDR3 = 0;
    TMOD = 0x01;  //设置T0为模式1
    TH0  = 0xFC;  //为T0赋初值0xFC67，定时1ms
    TL0  = 0x67;
    ET0  = 1;     //使能T0中断
    TR0  = 1;     //启动T0
    while (1);
}
/* 定时器0中断服务函数 */
void InterruptTimer0() interrupt 1
{
    static unsigned char i = 0;  //动态扫描的索引
    static unsigned char tmr = 0;  
    static unsigned char index = 0;  //图片刷新索引

    TH0 = 0xFC;  //重新加载初值
    TL0 = 0x67;
    //以下代码完成LED点阵动态扫描刷新
    P0 = 0xFF;   //显示消隐
    switch (i)
    {
        case 0: ADDR2=0; ADDR1=0; ADDR0=0; i++; P0=image[index+0]; break;
        case 1: ADDR2=0; ADDR1=0; ADDR0=1; i++; P0=image[index+1]; break;
        case 2: ADDR2=0; ADDR1=1; ADDR0=0; i++; P0=image[index+2]; break;
        case 3: ADDR2=0; ADDR1=1; ADDR0=1; i++; P0=image[index+3]; break;
        case 4: ADDR2=1; ADDR1=0; ADDR0=0; i++; P0=image[index+4]; break;
        case 5: ADDR2=1; ADDR1=0; ADDR0=1; i++; P0=image[index+5]; break;
        case 6: ADDR2=1; ADDR1=1; ADDR0=0; i++; P0=image[index+6]; break;
        case 7: ADDR2=1; ADDR1=1; ADDR0=1; i=0; P0=image[index+7]; break;
        default: break;
    }

    tmr++;
    if (tmr >= 80)  
    {
        tmr = 0;
        index++;
        if (index >= 32)  //图片索引达到32后归零
        {
            index = 0;
        }
    }
}

 已经在开发板上试过了，可以用