实验15

任务一

#include<iostream>
using namespace std;
int main()
{
	double ted=20.2;
	double *ptr = &ted;
	cout << "ted=" << ted << endl;
	cout << "*ptr=" << *ptr << endl;
	return 0;
}

任务二

#include<iostream>
using namespace std;
void ptr2()
{
	float treacle[10]={1,2,3,4,5,6,7,8,9,0},*ptr;
	ptr=&treacle[0];
	cout<<"first="<<*ptr<<endl;
	cout<<"final="<<*(ptr+9)<<endl;
}
int main()
{
	ptr2();
	return 0;
}

任务三

#include<iostream>
using namespace std;
void fun1(int a,int b,int c,int *one,int *two,int *three)
{
	if(a<b)
		if(a<c)
		{
			*one=a;
			if(b<c)
			{
				*two=b;
				*three=c;
			}
		}
		else
		{
			*one=c;
			*two=a;
			*three=b;
		}
	else if(b>c)
	{
		*one=c;
		*two=b;
		*three=a;
	}
	else if(a>c)
	{
		*one=b;
		*two=c;
		*three=a;
	}
	else
	{
		*one=b;
		*two=a;
		*three=c;
	}
}
int main()
{
	int a=10,b=9,c=8,x,y,z;
	fun1(a,b,c,&x,&y,&z);
	cout<<x<<' '<<y<<' '<<z<<endl;
}

方案二

#include<iostream>
using namespace std;
void fun1(int *a,int *b,int *c)
{
	int t;
	if (*a > *b)
	{
		t = *a;
		*a = *b;
		*b = t;
	}
	if (*a > *c)
	{
		t = *a;
		*a = *c;
		*c = t;
	}
	if (*c < *b)
	{
		t = *b;
		*b = *c;
		*c = t;
	}
}
int main()
{
	int a = 10, b = 9, c = 8;
	fun1(&a, &b, &c);
	cout << a << ' ' << b << ' ' << c << endl;
}

任务四

#include<iostream>
using namespace std;
double fun2(int *p,int n)
{
	double sum=0;
	for(int i=0;i<n;i++)
		{
		sum+=p[i];
		}
	return sum/n;
}
int main()
{
	int f[10]={1,2,3,4,5,6,7,8,9,10};
	cout<<fun2(f,10)<<endl;
	return 0;
}

版权声明:本文为River_Distance原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接和本声明。