C# \x 反斜杠x 16进制 编码

 str = System.Text.RegularExpressions.Regex.Replace(str, @"\\x(\w{2})", (a) =>
       {
          return Convert.ToChar(Convert.ToInt32(a.Value.Replace("\\x", ""),16)).ToString();
       });

调用接口时用到的, 接口返回带有\x 前缀的16进制编码字符 使用正则替换掉.

如何编码???

using System;
					
public class Program
{
	public static void Main()
	{
		
		char x1=':';
		char x2='!';
		
		Console.WriteLine(String.Format(@"\x{0:x2}", (ushort)x1));
		Console.WriteLine(String.Format(@"\x{0:x2}", (ushort)x2));
	}
}

输出:

\x3a
\x21