打印100内数字的逢7过(7的倍数不打印,数字中包含7的不打印):
i = 1
while i < 100:
if i % 7 == 0:
pass
elif i // 10 == 7:
pass
elif i % 10 == 7:
i += 1
continue
else:
print(i,end=" ")
i += 1
优化一下上面的代码:
i = 0
while i < 100:
i += 1
if i % 7 == 0 or i % 10 == 7 or i//10 == 7:
continue
else:
print(i)
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版权声明:本文为CSDN博主「托尼stark」的原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接及本声明。
原文链接:https://blog.csdn.net/qq_40808154/article/details/88728152