在C ++中将十进制转换为二进制

• Divide the number by 2 and save the remainder somewhere.

  将数字除以2，然后将其余部分保存在某处。

• Divide the quotient with 2 again and save the remainder somewhere.

  再次将商除以2，并将余数保存到某处。

• Repeat the process until 1 is left as quotient.

  重复该过程，直到将1保留为商。

• Now write the remainders in reverse order.

  现在，以相反的顺序写余数。

C ++中的十进制到二进制程序 (Program for Decimal to Binary in C++)

#include<iostream>
 
using namespace std;
 
int main()
{
	int d,n,i,j,a[50];
	cout<<"Enter a number:";
	cin>>n;
	cout<<"\nThe binary conversion of "<<n<<" is 1";
	
	for(i=1;n!=1;++i)
	{
		d=n%2;
		a[i]=d;
		n=n/2;
	}
	
	for(j=i-1;j>0;--j)
		cout<<a[j];
		
	return 0;
}

翻译自: https://www.thecrazyprogrammer.com/2011/03/c-program-to-convert-decimal-number-to-2.html