一般较复杂的写法：if(pouch.getStatus().equals("Finalized") || pouch.getStatus().equals("Ready")
|| pouch.getStatus().equals("Checkout") || pouch.getStatus().equals("Confirmed")
|| pouch.getStatus().equals("Book") || pouch.getStatus().equals("Started")
|| pouch.getStatus().equals("Inital") || pouch.getStatus().equals("Close")) {
// Body
}
1、使用matches实现if(pouch.getStatus().matches("Finalized|Ready|Checkout|Confirmed|Book|Started|Inital|Close")){
//your implementation goes here
}
2、使用字典集合判断
1)在集合中添加多个条件，从中实现 CollectionSet dict = new HashSet();
dict.add("Finalized");
dict.add("Ready");
dict.add("Checkout");
dict.add("Confirmed");
dict.add("Book");
dict.add("Started");
dict.add("Inital");
dict.add("Close");
2)contains检查输入值是否存在于集合中if (dict.contains(pouch.getStatus()))
{
// do your logic
}
3、使用Stream实现判断String status = pouch.getStatus();
if (Stream.of(
"Finalized",
"Ready",
"Checkout",
"Confirmed",
"Book",
"Started",
"Inital",
"Close")
.anyMatch(status::equals)) {
// Body
}
4、使用Arrays.asList()通过数组判断public String[] statusArray = new String[]{ "Finalized", "Ready","Checkout","Confirmed", "Book", "Started", "Inital", "Close"};
if( Arrays.asList(statusArray).contains(pouch.getStatus())){
//do something
}
或// Java 9 way of initializing List with one line
List statuses = List.of("Finalized", "Ready", "Checkout", "Confirmed",
"Book", "Started", "Inital", "Close");
if (statuses.contains(pouch.getStatus())) {
// Body
}
5、使用switch case判断switch (pouch.getStatus()) {
case "Finalized":
case "Ready":
case "Checkout":
case "Confirmed":
case "Book":
case "Started":
case "Inital":
case "Close":
// your code
break;
}