1081 检查密码(c++实现)

题目描述

思路分析

改了n遍都不知道错在哪，想了半天错误的可能，原来是因为直接cin >> password会没法读入密码中的空格，呵呵。

代码部分

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
 // ios::sync_with_stdio(0);
     int N;
	 cin >> N; getchar();
	 string password;
	 for(int i = 0; i < N; i++)
	 {
	     int countnum = 0, flagnum = 1, flagletter = 1;
	     // 可读入输入的密码中的空格
	     getline(cin , password);
	     if(password.size() < 6)
	          printf("Your password is tai duan le.");
	     else
	     {
	         for(int j = 0; j < password.size(); j++)
	         {
	             if(password[j] >= '0' && password[j] <= '9'	             {
	                   //存在数字
	                   flagnum = 0;
	                   countnum ++;
	               }
	               if( (password[j] >= 'A' && password[j] <= 'Z') || (password[j] >= 'a' && password[j] <= 'z') )
	               {
	                   //存在字母
	                   flagletter = 0;
	                   countnum ++;
	                }
	                if( password[j] == '.')
	                    countnum ++;
	            }
	            if(countnum != password.size())
	                printf("Your password is tai luan le.");
	            else if(flagnum == 1)
	                //没有数字
	                printf("Your password needs shu zi.");
	            else if(flagletter == 1)
	                //没有字母
	                printf("Your password needs zi mu.");
	            else
	                printf("Your password is wan mei.");
	        }
	        printf("\n");
	    }
	    return 0;
	}