杭电acm1002答案用C语言,杭电oj1002题求助,代码可以运行,和测试数据结果相同...

CODE:

#include

#include

#include

#include

int main(){

int n;

int a[1000], b[1000];

char a1[1001], b1[1001];

if (scanf("%d", &n) != EOF){

if (n<1 || n>20) return -1;

int tmp = 0;

for (tmp = 1; tmp <= n;tmp++){

if (scanf("%s%s", a1, b1) != EOF){

int a_len = 0, b_len = 0;

a_len = strlen(a1);

b_len = strlen(b1);

int i, j;

for ( i = a_len - 1; i >= 0; i--){

a[a_len - 1 - i] = a1[i] - '0';

}

for (j = b_len - 1; j >= 0; j--){

b[b_len - 1 - j] = b1[j] - '0';

}

int max_len = (a_len > b_len) ? a_len : b_len;

if (a_len > b_len){

int i = 0;

for (i = b_len; i <= max_len; i++){

b[i] = 0;

}

a[a_len] = 0;

}

else

{

int j = 0;

for (j = a_len; j <= max_len; j++){

a[j] = 0;

}

b[b_len] = 0;

}

//求和

int k;

for (k= 0; k <= max_len; k++){

a[k] += b[k];

if (a[k] >= 10){

a[k] -= 10;

a[k + 1] += 1;

}

}

printf("Case %d:\n%s + %s = ", tmp, a1, b1);

if (a[a_len] == 0){

int i = 0;

for (i = a_len - 1; i >= 0; i--)

{

printf("%d", a[i]);

}

}

else{

int i = 0;

for (i = a_len; i >= 0; i--)

{

printf("%d", a[i]);

}

}

}

if (tmp != n)

printf("\n\n");

else

printf("\n");

}

}

return 0;

}