List<People> list = new ArrayList<>();
//根据age对list分组
Map<String,List<People>> groupByAge = list.stream().collect(Collectors.groupingBy(People::getAge));
//根据age进行排序(reserve倒序)
List<People> peopleListSorted = list.stream().sorted(Comparator.comparing(People::getAge).reversed()).collect(Collectors.toList());
//提取age,并排序
List<String> ageList = list.stream().map(People::getAge).distinct().sorted().collect(Collectors.toList());
//提取年龄大于20的people
List<People> olderThan20 = list.stream().filter(e->Integer.parseInt(e.getAge()) > 20).collect(Collectors.toList());
//累加
BigDecimal totalMoney = list.stream().map(People::getMoney).reduce(BigDecimal.ZERO, BigDecimal::add);
//查询
People people = list.stream().filter(e->e.getAge().equals("20")).findFirst().orElse(null);
//List<People> -> Map<String,People> (name,people)
Map<String,People> map = list.stream().collect(Collectors.toMap(People::getName,n->n));
//查找流中最大值和最小值
List<Person> personList = generatePersonList();
Person olderOne = personList.stream().max(Comparator.comparing(Person::getAge)).orElse(null);
Person youngerOne = personList.stream().min(Comparator.comparing(Person::getAge)).orElse(null);
//对象去重
ArrayList<Person> collect = personList.stream().collect(Collectors.collectingAndThen(
Collectors
.toCollection(() -> new TreeSet<>(Comparator.comparingInt(Person::getAge))),
ArrayList::new));
对于深度嵌套的语句,可能需要多次判空,才能保证代码的健壮性,但是用if来实现,会有一堆的if语句,java8通过optinal比较优雅的解决了这个问题。
举个例子:
String isocode = user.getAddress().getCountry().getIsocode().toUpperCase();
用if判空
if (user != null) {
Address address = user.getAddress();
if (address != null) {
Country country = address.getCountry();
if (country != null) {
String isocode = country.getIsocode();
if (isocode != null) {
isocode = isocode.toUpperCase();
}
}
}
}用optional实现:
String isocode = Optional.ofNullable(user)
.map(User::getAddress)
.map(Address::getCountry)
.map(Country::getIsocode)
.orElse("default");
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