这有点笨拙,但这是我想出的：
SELECT
*
FROM
(
SELECT
a.ID AS EventID,
b.ID AS VideoID,
b.Filename,
(
CASE
WHEN a.Time < b.StartTime THEN UNIX_TIMESTAMP(b.StartTime) - UNIX_TIMESTAMP(a.Time)
WHEN a.Time > b.EndTime THEN UNIX_TIMESTAMP(a.Time) - UNIX_TIMESTAMP(b.EndTime)
END
) AS distance_factor
FROM
`Events` a
CROSS JOIN
video b
WHERE
NOT EXISTS
(
SELECT NULL
FROM Video
WHERE a.Time BETWEEN StartTime AND EndTime
)
) c
WHERE
c.distance_factor =
(
SELECT
MIN(CASE WHEN d.Time < e.StartTime THEN UNIX_TIMESTAMP(e.StartTime) - UNIX_TIMESTAMP(d.Time) WHEN d.Time > e.EndTime THEN UNIX_TIMESTAMP(d.Time) - UNIX_TIMESTAMP(e.EndTime) END)
FROM
`Events` d
CROSS JOIN
video e
WHERE d.ID = c.EventID
)
GROUP BY
c.EventID
这会返回事件的日期不在任何视频的任何时间范围内的事件,但是会返回距离该事件日期最近的视频.
现在唯一的一件事就是有些视频的秒差完全一样.我不知道您是否希望它返回2行,但是现在,我将GROUP BY放在其中,只选择其中一行.
让我知道它是如何工作的.