Given a roman numeral, convert it to an integer.
Input is guaranteed to be within the range from 1 to 3999.
// Source : https://oj.leetcode.com/problems/roman-to-integer/
// Author : Chao Zeng
// Date : 2014-12-20
//罗马字母的转化有点恶心。。。看wikipedia才懂
class Solution {
public:
int romanToInt(string s) {
map<char,int> m;
m['I'] = 1;
m['V'] = 5;
m['X'] = 10;
m['L'] = 50;
m['C'] = 100;
m['D'] = 500;
m['M'] = 1000;
int ans = 0;
int length = s.length();
for (int i = length - 1; i >= 0; i--){
if (i == length - 1){
ans = m[s[i]];
continue;
}
if (m[s[i]] >= m[s[i+1]])
ans += m[s[i]];
else
ans -= m[s[i]];
}
return ans;
}
};版权声明:本文为hnuzengchao原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接和本声明。