# 写一个函数，统计字符串中有几个字母，几个数字，几个空格，几个其他字符，并返回结果。

import re
def statistical(s):
	letter = "[a-zA-Z]"
	digital = "[0-9]"
	blank = "[ ]"
	letter_numbers = 0
	digital_numbers = 0
	blank_numbers = 0
	for i in s:
		if(re.match(letter,i)) != None:
			letter_numbers += 1
		if(re.match(digital,i)) != None:
			digital_numbers += 1
		if(re.match(blank,i)) != None:
			blank_numbers += 1
	others = len(s) - letter_numbers - digital_numbers - blank_numbers
	return letter_numbers,digital_numbers,blank_numbers,others


if __name__ == "__main__":
	s = "abc 123 ABC =-"
	print("字母的数量:"+str(statistical(s)[0]))
	print("数字的数量:" + str(statistical(s)[1]))
	print("空格的数量:" + str(statistical(s)[2]))
	print("其他的数量:" + str(statistical(s)[3]))

输出结果:

字母的数量:6
数字的数量:3
空格的数量:3
其他的数量:2

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