ajax第二次请求没有传值,ajax方法里能不能再放ajax

ajax方法里能不能再放ajax0

asad28232014.09.30浏览31次分享举报

function submit() {

var username = document.getElementById("username").value;

var password =document.getElementById("password").value;

$.ajax({

data: { username: username,password:password,method:'ajax'},

url: "/win_member_login.do",

type: "post",

success: function (msg) {

alert(msg);

var data = eval("(" + msg +")");

username = data.username;

alert(username);

alert("登陆成功");

$.ajax({

data: {username:username,method:'ajax'},

type: 'post',

url: "/loginAjaxT.do",

success: function (msg) {

}

});

window.location.href='loginAjaxT.do?username='+username;

}

});

}

第二个ajax里根本没传值进去，后台接受不到，应该怎么解决？