数组反转(倒叙)输出四种方法

public class ArrayDemo3 {

public static void main(String[] args) {
    //思路1.数组倒序输出
    /*int[] nums = {3, 1, 10, 5, 6};
    for (int i = nums.length - 1; i >= 0; i--) {
        System.out.println(nums[i]);
    }*/

    //思路2.新定义一个数组,倒着赋给新的数组
    /*int[] nums = {3, 1, 10, 5, 6};
    int[] newNums2 = new int[nums.length];
    for (int i = 0; i < nums.length; i++) {
        newNums2[i] = nums[nums.length - 1 - i];
    }
    nums = newNums2;
    System.out.println(Arrays.toString(nums));
    System.out.println(Arrays.toString(newNums2));*/

    //思路3:交换前后两个数
    /*int[] nums = {3, 1, 10, 5, 6};

    for (int i = 0; i < nums.length / 2; i++) {
        int temp = nums[i];
        nums[i] = nums[nums.length - 1 - i];
        nums[nums.length - 1 - i] = temp;
    }
    System.out.println(Arrays.toString(nums));*/

    //思路4.定义开始结束互换数据
    // 3,4,6,8,98
    // ↑        ↑
    /*int[] nums = {3, 1, 10, 5, 6, 55};
    int start = 0;
    int end = nums.length - 1;
    while (start < end) {
        int temp = nums[start];
        nums[start] = nums[end];
        nums[end] = temp;
        start++;
        end--;
    }
    System.out.println(Arrays.toString(nums));*/
}

}