我尝试在mac终端上运行多个python函数，对于这个程序，它们都返回语法错误def spam():
print "R"
spam()
它返回错误：
^{pr2}$
这是我能找到的最简单的函数。在
为了清楚一点，终端正在运行程序的其余部分，但它不能处理函数。在#!/usr/bin/python
import math
number = int(raw_input("What's your surd?"))
print type(number)
#Just to let us know what the input is
if type(number) == int:
print "Number is an integer"
else:
print "Please enter a number"
value = math.sqrt(number)
#Takes the number and square roots it
new_value = int(value)
#Turns square root of number into an integer
if type(new_value) == int:
print "Surd can be simplified"
print new_value
else:
print "Surd cannot be simplified"
print value
这个程序运行良好，即使它现在有点错误，但下面的程序返回与前一个函数相同的错误。在# define a function
def print_factors(x):
print("The factors of",x,"are:")
for i in range(1, x + 1):
if x % i == 0:
print(i)
num = int(input("What's your number? "))
print_factors(num)
为什么终端在没有语法错误的地方返回语法错误？在