Python：每日一题 161：打印字母三角形

Python源码：

def triangle(row):
    alphabet = ['%c' % i for i in range(65, 65+26)]
    for i in range(1, row+1):
        if i <= 26:
            string = ''.join(alphabet[:i] + list(reversed(alphabet[:i-1])))
            
        else:
            j = i - 26
            string = alphabet[:] + alphabet[:j] + list(reversed(alphabet[:] + alphabet[:j-1]))
            string = ''.join(string)
        print(' ' * (row-i) + string)
triangle(28)