数值的整数次方 java

数值的整数次方 java

题目描述
给定一个double类型的浮点数base和int类型的整数exponent。求base的exponent次方。

代码1：

public class Solution {
    public double Power(double base, int exponent) {
        double a = 1.0;
        if(exponent == 0){
            a = 1;
        }
        if(exponent > 0){
            for(int i = 0; i < exponent; i++){
                a = a * base;
            }
        }
        if(exponent < 0){
            exponent = - exponent;
            for(int i = 0; i < exponent; i++){
                a = a * base;
            }
            a = 1 / a;
        }
        return a;
    }
}

代码2：推荐

public class Solution {
    public double Power(double base, int exponent) {
        double a = 1.0;
        if(exponent == 0){
            a = 1;
        }
        if(exponent > 0 || exponent < 0){
            for(int i = 0; i < exponent || i < - exponent; i++){
                a = a * base;
            }
            if(exponent < 0){
                a = 1 / a;
            }
        }
        return a;
    }
}