Comparator.comparing报错:non-static method cannot be referenced from a static context

努力了不一定会成功,但是不努力就一定不会成功!!!

If you try hard, you may not succeed, but if you don't work hard, you will not succeed!!!

1、问题1:

问题:这篇博文问题:https://blog.csdn.net/weixin_41453111/article/details/104942362

Comparator.comparing报错:non-static method cannot be referenced from a static context

解决方法:不要连续调用.reversed()方法:

可以利用apache比较器工具包的reversedComparator方法;或者拆分成两个语句。

①ComparatorUtils.reversedComparator(Comparator.comparing(CategoryVo::getSortOrder));

②Comparator<CategoryVo> comparator = Comparator.comparing(CategoryVo::getSortOrder);

       .sorted(comparator.reversed());

2、问题2:

依赖泛型属性比较。

public class User<T> {

    private String name;

    private Integer age;

    private T obj;
}
Comparator<User> comparing = Comparator.comparing(User::getObj);

依赖obj参数排序,此时会报错。

解决办法:泛型参数T需要限定实现了Comparable<>接口。

public class User<T extends Comparable<T>> {

    private String name;

    private Integer age;

    private T obj;

}

这样就解决了。

本质原因分析:

Comparator.comparing源码:

    public static <T, U extends Comparable<? super U>> Comparator<T> comparing(
            Function<? super T, ? extends U> keyExtractor)
    {
        Objects.requireNonNull(keyExtractor);
        return (Comparator<T> & Serializable)
            (c1, c2) -> keyExtractor.apply(c1).compareTo(keyExtractor.apply(c2));
    }

其中限定了U类型必须是继承Comparable<? super U>接口。


版权声明:本文为qq_29545781原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接和本声明。