我使用$ .ajax()函数在我的应用程序中调用servlet,并将请求转发到anoth或jsp页面并设置请求属性.....我只是想知道是否是在基于ajax的servelt中转发请求和设置请求参数的好方法? 这里是我的示例代码.....
var id= $("#id").val();
$("#add-btn").click(function(e) {
e.preventDefault();
var dataString ='action=insert'+'&id='+id
console.log(dataString);
$.ajax({
type: "POST",
url: "RecordHandler",
data: dataString,
success: function(data){
console.log('Add');
$('body').html(data);
$('body').prepend('
Record Added Succesfully
}
});
});
,这里是我的servlet代码......
private static String UserRecord = "/list.jsp";
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException{
String redirect = "";
String action = request.getParameter("action");
if (action.equalsIgnoreCase("insert")) {
String id= request.getParameter("id");
int uid = Integer.parseInt(id);
RecordBean record = new RecordBean();
record.setId(uid);
dao.addRecord(record);
redirect = UserRecord;
request.setAttribute("records", dao.getAllRecords()); //Is it good approach to set request attribute in ajax based servlet?
System.out.println("Record Added Successfully");
RequestDispatcher view = request.getRequestDispatcher(redirect);//Is it good approach to redirect request in ajax based servlet?
view.forward(request, response);
}
如何使用AJAX无刷新页面做.... .. 即使我在使用ajax成功方法时使用window.location.herf =“list.jsp”它正在刷新页面
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当然...为什么不呢?当然,你可以用JSON或其他现代的东西做到这一点。但是,从一个servlet重定向到一个jsp,并在成功的ajax调用之后显示它的内容是一种标准方式 - 恕我直言。 –
+0
好的,谢谢你的评论 –