Java中根据时间进行序号排序，时间+空位补0+序号

```java
import org.junit.Test;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

import javax.xml.crypto.Data;
import java.text.SimpleDateFormat;
import java.time.LocalDateTime;
import java.util.*;
import java.text.NumberFormat;


public class OrderNumberUtils {
    private static final Logger logger = LoggerFactory.getLogger(OrderNumberUtils.class);

    /**
     *序号共19位
     *指定位数，时间+空位补0+序号
     * */
    public static List<Map<String, Object>> orderNumber(List<Map<String, Object>> mapList) {
        // 获取的List的数据长度
        int size = mapList.size();
        /**
         *左边补充空位,用0去补充
         * */
        NumberFormat nf = NumberFormat.getInstance();
        //设置是否使用分组
        nf.setGroupingUsed(false);
        //设置最大整数位数
        nf.setMaximumIntegerDigits(11);
        //设置最小整数位数
        nf.setMinimumIntegerDigits(11);

        //获取当前日期
        Date date = new Date();
        SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyyMMdd");
        String format = simpleDateFormat.format(date);
        logger.info("simpleDateFormat" + format);

        for (int i = 0; i <size; i++) {
            mapList.get(i).put("A", format + nf.format(i+1));
        }
        logger.info("设置完成之后的序号(拼接完成后的正确数据):" + mapList);
        return mapList;
    }
    public static void main(String[] args) {
        List<Map<String, Object>> mapList = new ArrayList<>();
        Map<String, Object> map = new HashMap<>();
        map.put("A", "22");
        map.put("B", "44");
        map.put("C", "66");
        mapList.add(map);
        Map<String, Object> map3 = new HashMap<>();
        map3.put("A", "22");
        map3.put("B", "44");
        map3.put("C", "66");
        mapList.add(map3);
        Map<String, Object> map4 = new HashMap<>();
        map4.put("A", "22");
        map4.put("B", "44");
        map4.put("C", "66");
        mapList.add(map4);
        orderNumber(mapList);
    }
}