井字棋游戏(C语言).doc
井字棋小游戏(C语言)
说明:该游戏的源代码在后面!
//源代码如下:
#include
#include
#include
#include
//这里少了人机对弈的模块,所以要增加个搜索算 。
//已经有的是双人对弈的模块,有时间再去弄弄!
char chess[8][8], _isexit = '0', A = '*', B = '#', role = '*', Do = '1';
int flag[8][8], Round = 0, result = 3, count = 0;
#include "Initilize.h"
#include "Print_chess.h"
#include "Choose.h"
#include "Operation.h"
#include "Judge.h"
int main() {
//getch();
chooseRole();
getchar(); //缓冲下!
return 0;
}
//#include
void print_chess() {
int i, j;
system("cls\n"); //清屏操作;
printf(" 我现在持 %c 棋:\n", role);
printf(" 第 %d 回合:\n\n", Round);
for(i = 1;i <= 6;i++)
{
if(2 == i || 4 == i) {printf(" __"); chess[i][6] = '_';}
else printf(" ");
for(j = 1;j <= 6;j++)
printf("%c",chess[i][j]);
if(2 == i || 4 == i) printf("_");
printf("\n");
}
//测试:
for(i = 1;i < 6;i++)
{ if(2 == i || 4 == i) continue;
for(j = 1;j < 6;j++)
{
if(2 == j || 4 == j) continue;
printf("%d ",flag[i][j]);
}
printf("\n");
}
return ;
}
//#include
//#include
void theResult();
int judge();
void operation();
void choose();
void chooseRole();
void delay();
void delay2();
void chooseRole() {
printf(" 请选择先手:(1 / 0) \n");
// 1 代表先手,0 代表后手;
initilize();
while(1) {
printf(" ");
role = getch();
printf("%c\n",role);
if('0' == role || '1' == role) break;
role = ' ';
print_chess();
printf(" 输入错误,请重新输入!\n");
delay2();
}
delay2();
if('0' == role) role = A;
else role = B;
while(1) {
print_chess();
judge();
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