\sum\limits_{i=1}^n i^2 = \frac{n(n+1)(2n+1)}{6} 加和公式为∑ i = 1 n i 2 = n ( n + 1 ) ( 2 n + 1 ) 6 \sum\limits_{i=1}^n i^2 = \frac{n(n+1)(2n+1)}{6}i=1∑ni2=6n(n+1)(2n+1)
\sum\nolimits_{P_i \in Paths(I)} Probes(P_{i}) 加和公式为 ∑ P i ∈ P a t h s ( I ) P r o b e s ( P i ) \sum\nolimits_{P_i \in Paths(I)} Probes(P_{i})∑Pi∈Paths(I)Probes(Pi)
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