java hasnext 怎么用,Java - 如何在使用hasNext()条件时突破?

I am writing a simple program to calculate the average of a set of numbers. You get the numbers using Scanner, so I am using while loop with .hasNext() as a condition. However the loop is infinite.

Is it possible to break out of it without writing some certain word like "stop" in the input?

public class main {

public static void main(String[] args){

Scanner Input = new Scanner(System.in);

int count = 0;

int temp;

int sum = 0;

while(Input.hasNextInt()){

count++;

temp = Input.nextInt();

sum += temp;

System.out.println(temp);

System.out.println(count);

} // End of while

double average = sum / count;

System.out.println("The average is: " + average);

} // End of method main

}

解决方案

The break; statement can be sued to... well... break out of an iteration. And by iteration I mean you can get out of a for too, for example.

You have to define WHEN do you want to break out of the iteration and then do something like this:

while(Input.hasNextInt(Input)){

if(condition())

break;

count++;

temp = Input.nextInt();

sum += temp;

System.out.println(temp);

System.out.println(count);

}

Otherwise, you can make an auxiliary method that defines if the iteration should keep on going, like this one:

private boolean keepIterating(Scanner in) {

boolean someOtherCondition = //define your value here that must evaluate to false

//when you want to stop looping

return Input.hasNextInt() && someOtherCondition;

}

Method that you will have to invoke in your while:

while(keepIterating()){

count++;

temp = Input.nextInt();

sum += temp;

System.out.println(temp);

System.out.println(count);

}