
[{id:1, pid:0, name:'沃尔玛', childrens:[
{id:2, pid:1, name:'生鲜区', childrens:[
{id:4, pid:2, name:'鱼'},
{id:5, pid:2, name:'牛肉'}
]},
{id:3, pid:1, name:'日用品区',childrens:[
{id:6, pid:3, name:'卫生纸'},
{id:7, pid:3, name:'牙刷'}
]}
]}
扁平数据结构[{id:1, pid:0, name:'沃尔玛'},
{id:2, pid:1, name:'生鲜区'},
{id:3, pid:1, name:'日用品区'},
{id:4, pid:2, name:'鱼'},
{id:5, pid:2, name:'牛肉'},
{id:6, pid:3, name:'卫生纸'},
{id:7, pid:3, name:'牙刷'},
{id:8, pid:7, name:'电动牙刷'},
{id:9, pid:7, name:'普通牙刷'}]
02 树形转扁平 思路 ( 递归方法 ): 1、循环数组,取出每个对象进行判断 2、如果有children属性,将children传到flat函数重复执行,并将执行的结构返回数组,加入到新数组中。然后删除当前对象的childrens属性 3、不管是否有childrens属性,都要将当前对象解构,然后加入新数组中 代码如下:function flat(arr){ var newArr=[];//申请新数组 for(var i=0;i
03 示例代码 写了一个DEMO 代码如下:var data=[{id:1, pid:0, name:'沃尔玛', childrens:[
{id:2, pid:1, name:'生鲜区', childrens:[
{id:4, pid:2, name:'鱼'},
{id:5, pid:2, name:'牛肉'}
]},
{id:3, pid:1, name:'日用品区',childrens:[
{id:6, pid:3, name:'卫生纸'},
{id:7, pid:3, name:'牙刷'}
]}
]}];
var flatArr= flat(data);
//递归
function flat(arr){
let newArr=[];
for(let i=0;i
if(arr[i].childrens){//childrens存在
newArr.push(...flat(arr[i].childrens));
delete arr[i].childrens;
}
newArr.push({...arr[i]});
}
return newArr;
}
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