python中列表排序如果内容相同_在python中以相同的顺序排列两个列表

我有一个关于洗牌的问题，但首先，我的代码是：from psychopy import visual, event, gui

import random, os

from random import shuffle

from PIL import Image

import glob

a = glob.glob("DDtest/targetimagelist1/*")

b = glob.glob("DDtest/distractorimagelist1/*")

target = a

distractor = b

pos1 = [-.05,-.05]

pos2 = [.05, .05]

shuffle(a)

shuffle(b)

def loop_function_bro():

win = visual.Window(size=(1280, 800), fullscr=True, screen=0, monitor='testMonitor', color=[-1,-1,-1], colorSpace='rgb')

distractorstim = visual.ImageStim(win=win,

image= distractor[i], mask=None,

ori=0, pos=pos1, size=[0.5,0.5],

color=[1,1,1], colorSpace='rgb', opacity=1,

flipHoriz=False, flipVert=False,

texRes=128, interpolate=True, depth=-1.0)

targetstim= visual.ImageStim(win=win,

image= target[i], mask=None,

ori=0, pos=pos2, size=[0.5,0.5],

color=[1,1,1], colorSpace='rgb', opacity=1,

flipHoriz=False, flipVert=False,

texRes=128, interpolate=True, depth=-2.0)

distractorstim.setAutoDraw(True)

targetstim.setAutoDraw(True)

win.flip()

event.waitKeys(keyList = ['space'])

for i in range (2):

loop_function_bro()

这段代码随机洗牌一组图像并显示它们。然而，我想它是在相同的顺序洗牌图像，以便两个列表显示在相同的随机顺序。有办法吗？在

干杯，：)