解题思路:
记录每一个数字的出现次数并比较
注意事项:
参考代码:
#include
int main(void)
{
int i, j, n, count, min, digit, count1;
int num[50000];
scanf("%d", &n);
for (i = 0;i < n;i++)
scanf("%d", &num[i]);
for (i = 0;i < n;i++)
for (j = i + 1, min = num[i];j < n;j++)
if (min > num[j])
{
min = num[j];
num[j] = num[i];
num[i] = min;
}
for (i = 0, digit = num[i], count = 1;i < n;i++)
{
if (num[i] == num[i + 1])
count++;
else
break;
}
for (j = i + 1, count1 = 1;j < n;j++)
{
if (num[j] == num[j + 1])
count1++;
else
{
if (count1 > count)
{
count = count1;
digit = num[j];
count1 = 1;
}
else
count1 = 1;
}
}
printf("%d\n%d", digit, count);
return 0;
}