Description
In this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequence of n distinct integers by swapping two adjacent sequence elements until the sequence is sorted in ascending order. For the input sequence Ultra-QuickSort produces the output
Your task is to determine how many swap operations Ultra-QuickSort needs to perform in order to sort a given input sequence.
Input
The input contains several test cases. Every test case begins with a line that contains a single integer n < 500,000 -- the length of the input sequence. Each of the the following n lines contains a single integer 0 ≤ a[i] ≤ 999,999,999, the i-th input sequence element. Input is terminated by a sequence of length n = 0. This sequence must not be processed.
Output
For every input sequence, your program prints a single line containing an integer number op, the minimum number of swap operations necessary to sort the given input sequence.
Sample Input
5 9 1 0 5 4 3 1 2 3 0
Sample Output
6
0
#include<stdio.h> #include<algorithm> #include<string.h> using namespace std; pair<int,int>v[500005]; int dp[500004],a[500005],b[500005]; int bit[500005+1],n; int sum(int i); void add(int i,int x); int main() { int i,j,k; while(scanf("%d",&n),n!=0) { for(i=0;i<n;i++) { scanf("%d",&v[i].first); v[i].second=i; } sort(v,v+n); b[0]=1; a[v[0].second]=1; for(i=1;i<n;i++) { if(v[i].first>v[i-1].first) b[i]=b[i-1]+1; else b[i]=b[i-1]; a[v[i].second]=b[i]; } memset(bit,0,sizeof(bit)); long long ans; ans=0; for(i=0;i<n;i++) { ans+=i-sum(a[i]); add(a[i],1); } printf("%lld\n",ans); } return 0; } int sum(int i) { int s=0; while(i>0) { s+=bit[i]; i-=i& -i; } return s; } void add(int i,int x) { while(i<=n) { bit[i]+=x; i+=i & -i; } }
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