类字节大小,字节对齐相关

1、空类为1字节,虚函数指针为4字节(字节按double对齐时为8字节),子类在父类的字节大小上面累加

class B
{
	double a; //8字节
	int b;

public:
	virtual ~B(){ cout << "B::~B()" << endl; }
};

class D : public B
{
 	int i;
 	int j;
public:
	virtual ~D() { cout << "D::~D()" << endl; }
};

int main(void)
{
	cout << "sizeB:" << sizeof(B) << " sizeD:" << sizeof(D) << endl;
	B *pb = new D[2];

	delete[] pb;

	return 0;
}
类B按8字节对齐,类D按4字节对齐,所以sizeof(B): 24  sizeof(D):32
<span style="font-family: Arial, Helvetica, sans-serif;">#pragma pack(1)</span>
在B类前面加上#pragma pack(1)时,则按1字节对齐, <span style="font-family: Arial, Helvetica, sans-serif;">所以sizeof(B): 16  sizeof(D):24


版权声明:本文为zheng2263原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接和本声明。