SpringBoot在Controller中接收LocalDate/LocalDateTime

1.mapperObject对象

@Configuration
public class MapperObjectConfig {

	@Bean(name = "mapperObject")
	public ObjectMapper getObjectMapper() {
		return new ObjectMapper().registerModule(new ParameterNamesModule()).registerModule(new Jdk8Module())
				.registerModule(new JavaTimeModule());
	}

}

另外一种方法,在yml文件中配置这个就不需要mapperObject对象了

spring:
  jackson:
    date-format: yyyy-MM-dd HH:mm:ss

2.实体类的LocalDate/LocalDateTime属性上加注解

public class TimeBean {

	@DateTimeFormat(pattern = "yyyy-MM-dd HH:mm:ss")
	private LocalDateTime nowTime;

	@DateTimeFormat(pattern = "yyyy-MM-dd")
	private LocalDate nowDate;
}

3.直接Controller接收实体对象

	@RequestMapping("/test")
	public void restController(TimeBean bean) {
		System.out.println(bean.getNowDate());
		System.out.println(bean.getNowTime());
	}

前端参数示例:

注意 LocalDateTime不能使用 pattern ="yyyy-MM-dd" 

否则报错:

Failed to convert property value of type 'java.lang.String' to required type 'java.time.LocalDateTime' for property 'nowTime'; nested exception is org.springframework.core.convert.ConversionFailedException: Failed to convert from type [java.lang.String] to type [@org.springframework.format.annotation.DateTimeFormat java.time.LocalDateTime] for value '2017-07-02 11:10:11'; nested exception is java.lang.IllegalArgumentException: Parse attempt failed for value [2017-07-02 11:10:11]

没错,就是这么简单....