一、简单说明
本以为mybatis的example可以搞定group by，后面看到说不行
于是曲线救国，直接查出一个list，然后再用java对数据进行操作
不过话说回来，这样写是比写sql麻烦一点，但是个人感觉这样效率会高一点(未做对比测试)
二、需求说明
查出数据库中，过去30天，每个用户(merId)每天的发送条数
改进版，在1的基础上，加上所有日期的统计信息，对应日期没记录也加上
三、所用技术概要
jodatime：方便对时间进行操作，转换等
stream：对java进行操作，很是方便，此处只是stream用法的冰山一角
四、代码实现
省略了生成的实体类、mapper、example等
需求1实现
public Map coountDays(String merId){
SmsCustomerSendDetailExample example = new SmsCustomerSendDetailExample();
// 查询条件
DateTime dt = new DateTime();
// 当天00:00:00往前推30天
DateTime days = dt.withTimeAtStartOfDay().minusDays(30);
Criteria criteria = example.createCriteria();
criteria.andCustomerIdEqualTo(merId);
criteria.andCreateTimeBetween(days.toDate(),dt.toDate());
List details = sendDetailMapper.selectByExample(example);
// 对时间进行更改，清洗为yyyyMMdd(后面按天分组用)
for (SmsCustomerSendDetail detail : details) {
DateTime dateTime = new DateTime(detail.getCreateTime().getTime()).withTimeAtStartOfDay();
detail.setCreateTime(dateTime.toDate());
}
//根据日期分组
Map> dateListMap = details.stream()
.collect(Collectors.groupingBy(SmsCustomerSendDetail::getCreateTime));
// 遍历map,求出当天记录的条数
HashMap resMap = new HashMap<>(128);
for (Entry> detailEntry:dateListMap.entrySet()){
String day = new DateTime(detailEntry.getKey().getTime()).toString("yyyyMMdd");
int daySize = detailEntry.getValue().size();
resMap.put(Integer.valueOf(day),daySize);
}
// 排序
Stream> st = resMap.entrySet().stream();
Map result = new LinkedHashMap<>(32);
st.sorted(Comparator.comparing(e -> e.getKey())).forEach(e -> result.put(e.getKey(), e.getValue()));
return result;
}
结果：{20180306:44,20180307:14,20180308:9}
需求2实现
public Map coountDays(String merId){
SmsCustomerSendDetailExample example = new SmsCustomerSendDetailExample();
// 查询条件
DateTime dt = new DateTime();
// 当天00:00:00往前推30天
DateTime days = dt.withTimeAtStartOfDay().minusDays(30);
Criteria criteria = example.createCriteria();
criteria.andCustomerIdEqualTo(merId);
criteria.andCreateTimeBetween(days.toDate(),dt.toDate());
List details = sendDetailMapper.selectByExample(example);
// 对时间进行更改，清洗为yyyyMMdd(后面按天分组用)
for (SmsCustomerSendDetail detail : details) {
DateTime dateTime = new DateTime(detail.getCreateTime().getTime()).withTimeAtStartOfDay();
detail.setCreateTime(dateTime.toDate());
}
//根据日期分组
Map> dateListMap = details.stream()
.collect(Collectors.groupingBy(SmsCustomerSendDetail::getCreateTime));
// 遍历map,求出当天记录的条数
HashMap resMap = new HashMap<>(128);
for (Entry> detailEntry:dateListMap.entrySet()){
String day = new DateTime(detailEntry.getKey().getTime()).toString("yyyyMMdd");
int daySize = detailEntry.getValue().size();
resMap.put(Integer.valueOf(day),daySize);
}
// 添加过去30天所有天为key,从resMap中取出有数据的，否则为0
Map result = new LinkedHashMap<>(32);
for (int i = 0; i < 30; i++) {
String yyyyMMdd = days.plusDays(i).toString("yyyyMMdd");
Integer day = Integer.valueOf(yyyyMMdd);
int value = 0;
if (resMap.containsKey(day)){
value = resMap.get(day);
}
result.put(Integer.valueOf(yyyyMMdd),value);
}
return result;
}
结果：{20180213:0,20180214:0,20180215:0,20180216:0,20180217:0,20180218:0,20180219:0,20180220:0,20180221:0,20180222:0,20180223:0,20180224:0,20180225:0,20180226:0,20180227:0,20180228:0,20180301:0,20180302:0,20180303:0,20180304:0,20180305:0,20180306:44,20180307:14,20180308:9,20180309:0,20180310:0,20180311:0,20180312:0,20180313:0,20180314:0}