A1:是的，他们使用同一个连接池。在
A2：这不是一个好的做法。因为您无法控制此实例的初始化。另一种选择是使用singleton。在import redis
class Singleton(type):
"""
An metaclass for singleton purpose. Every singleton class should inherit from this class by 'metaclass=Singleton'.
"""
_instances = {}
def __call__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls]
class RedisClient(object):
def __init__(self):
self.pool = redis.ConnectionPool(host = HOST, port = PORT, password = PASSWORD)
@property
def conn(self):
if not hasattr(self, '_conn'):
self.getConnection()
return self._conn
def getConnection(self):
self._conn = redis.Redis(connection_pool = self.pool)
那么RedisClient将是一个单例类。无论调用client = RedisClient()多少次，都会得到相同的对象。在
所以你可以像这样使用它：
^{pr2}$
第一次调用client = RedisClient()时，将实际初始化该实例。在
或者您可能希望基于不同的参数获取不同的实例：class Singleton(type):
"""
An metaclass for singleton purpose. Every singleton class should inherit from this class by 'metaclass=Singleton'.
"""
_instances = {}
def __call__(cls, *args, **kwargs):
key = (args, tuple(sorted(kwargs.items())))
if cls not in cls._instances:
cls._instances[cls] = {}
if key not in cls._instances[cls]:
cls._instances[cls][key] = super(Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls][key]