编程题--任意给出一个四位数， 把它重新组成一个四位的最大数和一个最小数， 算出两者间的差...

*程序头部的注释结束*/

#include <iostream>
using namespace std;
int main ()
{
	int abcd, a, b, c, d, m, i, q, j, num[4], max, min;
	
	cout << "请输入一个四位数：";
	cin >> abcd;
	a = abcd / 1000;
	b = (abcd % 1000) / 100;
	c = ((abcd % 1000) % 100) / 10;
	d = ((abcd % 1000) % 100) % 10;
	num[0] = a;
	num[1] = b;
	num[2] = c;
	num[3] = d;
	for (i = 0; i < 3; i++)
	{
		for (j = 0; j < (3-i); j++)
		{
			if (num[j] < num[j+1])
			{
				m = num[j];
				num[j] = num[j+1];
				num[j+1] = m;
			}
		}
	}
	max = num[0]*1000+num[1]*100+num[2]*10+num[3];
	cout<<"最大数为：";
	cout<<max<<endl;
	for (i = 0; i < 3; i++)
	{
		for (j = 0; j < (3-i); j++)
		{
			if (num[j] > num[j+1])
			{
				m = num[j];
				num[j] = num[j+1];
				num[j+1] = m;
			}
		}
	}
	min = num[0]*1000+num[1]*100+num[2]*10+num[3];
	cout<<"最小数为：";
	cout<<min<<endl;
	q = max - min;
	cout << max << "-" << min << "=" << q << endl;
	return 0;
}