先来看一下需求:
sql语句:select date_format(creatTime,"%Y-%m-%d") as days,count(id) as num,sum(money) as money
from `order` group by days;
结果如下:解决方法:使用 CASE WHEN 字段 IS NOT NULL THEN 值 ELSE 0 END 示例代码:select date_format(creatTime,"%Y-%m-%d") as days,count(id) as num,
(CASE WHEN SUM(money) IS NOT NULL THEN SUM(money) ELSE 0 END) AS money
from `order` group by days;
最终效果: