oracle 查询重复的语句,Oracle查询并删除重复记录的SQL语句

Oracle查询并删除重复记录的SQL语句

2010-07-20 00:00出处:中国IT实验室作者:佚名【我要评论】 [导读]查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断。

企业软件热点文章

Java调用Dll存在指针或变参的解决方法 Oracle中非默认方式创建外键的使用

查询及删除重复记录的SQL语句

1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断

select * from people

where peopleId in (select peopleId from people group by peopleId having count(peopleId) >1)

2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有 rowid最小的记录

delete from people

where peopleId in (select peopleId from people group by peopleId having count(peopleId) >1)

and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

注:rowid为oracle自带不用该.....

3、查找表中多余的重复记录(多个字段)

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) >1)

4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录

delete from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) >1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) >1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

(二)

比方说

在A表中存在一个字段“name”,

而且不同记录之间的“name”值有可能会相同,

现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;

Select Name,Count(*) From A Group By Name Having Count(*) >1

如果还查性别也相同大则如下:

Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) >1

(三)

方法一

declare @max integer,@id integer

declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1

open cur_rows

fetch cur_rows into @id,@max

while @@fetch_status=0

begin

select @max = @max -1

set rowcount @max

delete from 表名 where 主字段 = @id

fetch cur_rows into @id,@max

end

close cur_rows

set rowcount 0 方法二

"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所