问题描述:
一所大学有 2 个数据表,分别是 student 和 department ,这两个表保存着每个专业的学生数据和院系数据。
写一个查询语句,查询 department 表中每个专业的学生人数 (即使没有学生的专业也需列出)。
将你的查询结果按照学生人数降序排列。 如果有两个或两个以上专业有相同的学生数目,将这些部门按照部门名字的字典序从小到大排列。
student 表格如下:
| Column Name | Type |
|--------------|-----------|
| student_id | Integer |
| student_name | String |
| gender | Character |
| dept_id | Integer |
/*
Navicat Premium Data Transfer
Source Server : 本地数据库
Source Server Type : MySQL
Source Server Version : 80013
Source Host : localhost:3306
Source Schema : rxttest
Target Server Type : MySQL
Target Server Version : 80013
File Encoding : 65001
Date: 03/11/2021 14:54:06
*/
SET NAMES utf8mb4;
SET FOREIGN_KEY_CHECKS = 0;
-- ----------------------------
-- Table structure for student
-- ----------------------------
DROP TABLE IF EXISTS `student`;
CREATE TABLE `student` (
`id` int(10) NOT NULL AUTO_INCREMENT,
`student_name` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci DEFAULT NULL,
`gender` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci DEFAULT NULL,
`dept_id` int(100) DEFAULT NULL,
PRIMARY KEY (`id`) USING BTREE
) ENGINE = InnoDB CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Dynamic;
-- ----------------------------
-- Records of student
-- ----------------------------
INSERT INTO `student` VALUES (1, 'Jack', 'M', 1);
INSERT INTO `student` VALUES (2, 'mark', 'F', 2);
INSERT INTO `student` VALUES (3, 'June', 'M', 1);
SET FOREIGN_KEY_CHECKS = 1;
其中, student_id 是学生的学号, student_name 是学生的姓名, gender 是学生的性别, dept_id 是学生所属专业的专业编号。
department 表格如下:
| Column Name | Type |
|-------------|---------|
| dept_id | Integer |
| dept_name | String |
dept_id 是专业编号, dept_name 是专业名字。
/*
Navicat Premium Data Transfer
Source Server : 本地数据库
Source Server Type : MySQL
Source Server Version : 80013
Source Host : localhost:3306
Source Schema : rxttest
Target Server Type : MySQL
Target Server Version : 80013
File Encoding : 65001
Date: 03/11/2021 14:54:18
*/
SET NAMES utf8mb4;
SET FOREIGN_KEY_CHECKS = 0;
-- ----------------------------
-- Table structure for department
-- ----------------------------
DROP TABLE IF EXISTS `department`;
CREATE TABLE `department` (
`id` int(100) NOT NULL,
`dept_name` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci DEFAULT NULL,
PRIMARY KEY (`id`) USING BTREE
) ENGINE = InnoDB CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Dynamic;
-- ----------------------------
-- Records of department
-- ----------------------------
INSERT INTO `department` VALUES (1, 'Engineering ');
INSERT INTO `department` VALUES (2, 'Science');
INSERT INTO `department` VALUES (3, 'Law');
SET FOREIGN_KEY_CHECKS = 1;
这里是一个示例输入:
student 表格:
| student_id | student_name | gender | dept_id |
|------------|--------------|--------|---------|
| 1 | Jack | M | 1 |
| 2 | Jane | F | 1 |
| 3 | Mark | M | 2 |
department 表格:
| dept_id | dept_name |
|---------|-------------|
| 1 | Engineering |
| 2 | Science |
| 3 | Law |
示例输出为:
| dept_name | student_number |
|-------------|----------------|
| Engineering | 2 |
| Science | 1 |
| Law | 0 |
sql:
select a.dept_name as 'dept_name',(select count(*) from student as b where b.dept_id=a.id) as 'student_number'
from department as a
order by student_number desc,dept_name Asc;
我要刷100道算法题,第88道