python中能被3整除的数_可被3整除的值

是的。你想要的是if y % 3 == 0:

# whatever you want to do with those numbers.

如果您想在列表中列出它们,可以使用以下理解:

^{pr2}$

对OP意见的回复

“那么我现在如何访问p变量中的这些字符串值,以确定它们是否可以被3整除?”在

不能:字符串不能被整型整除。我希望您需要的是将数字部分转换为整数并测试。在

取p值,跳过括号,然后转换。我将把代码分解成更小的步骤;您可以在看到过程后将其组合起来:for y in itertools.permutations(l, i):

s = str(y).replace(‘,’, ”)

p = s.replace(‘ ‘, ”)

num_str = p[1:-1]

if len(num_str) > 0:

value = int(num_str)

if value % 3 == 0:

print value, “is divisible by 3”

else:

print value, “does not have trinary nature”

else:

print p, “empty number”

输出:() empty number

3 is divisible by 3

3 is divisible by 3

7 does not have trinary nature

33 is divisible by 3

37 does not have trinary nature

33 is divisible by 3

37 does not have trinary nature

73 does not have trinary nature

73 does not have trinary nature

337 does not have trinary nature

373 does not have trinary nature

337 does not have trinary nature

373 does not have trinary nature

733 does not have trinary nature

733 does not have trinary nature