lambda表达式对List集合进行排序的两种姿势---改变/不改变原List集合

1. 改变原list集合

  • code
class NrscDemoApplicationTests {

    @Data
    @AllArgsConstructor
    @NoArgsConstructor
    static class Human {
        private String name;
        private int age;
    }

    @Test
    void changeOriginalList() {

        List<Human> humans = Lists.newArrayList(
                new Human("yoyo", 12),
                new Human("yoki", 12),
                new Human("nrsc", 10),
                new Human("nrfx", 10));

        //排序
        humans.sort(Comparator.comparing(Human::getAge).thenComparing(Human::getName));
        System.out.println(humans);

    }
}
  • 结果截图

在这里插入图片描述

2. 不改变原list集合

  • code
class NrscDemoApplicationTests {

    @Data
    @AllArgsConstructor
    @NoArgsConstructor
    static class Human {
        private String name;
        private int age;
    }

    @Test
    void changeOriginalList() {

        List<Human> humans = Lists.newArrayList(
                new Human("yoyo", 12),
                new Human("yoki", 12),
                new Human("nrsc", 10),
                new Human("nrfx", 10));

        //排序
        List<Human> collect = humans.stream()
                .sorted(Comparator.comparing(Human::getAge).thenComparing(Human::getName))
                .collect(Collectors.toList());

        System.err.println(humans);
        System.out.println(collect);

    }
}
  • 结果截图

在这里插入图片描述


版权声明:本文为nrsc272420199原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接和本声明。